12th Eötvös Competition Problems 1905



1.  For what positive integers m, n can we find positive integers a, b, c such that a + mb = n and a + b = mc. Show that there is at most one such solution for each m, n.
2.  Divide the unit square into 9 equal squares (forming a 3 x 3 array) and color the central square red. Now subdivide each of the 8 uncolored squares into 9 equal squares and color each central square red. Repeat n times, so that the side length of the smallest squares is 1/3n. How many squares are uncolored? What is the total red area as n → ∞?


3.  ABC is a triangle and R any point on the segment AB. Let P be the intersection of the line BC and the line through A parallel to CR. Let Q be the intersection of the line AC and the line through B parallel to CR. Show that 1/AP + 1/BQ = 1/CR. 

Solutions

Problem 1
For what positive integers m, n can we find positive integers a, b, c such that a + mb = n and a + b = mc. Show that there is at most one such solution for each m, n.
Solution
We fix c and solve for a and b.
We have n = a + mb = a + m(mc - a)= mc+1 - a(m-1). Hence (n-1)/(m-1) = (mc+1-1)/(m-1) - a. So a = (mc+1-1)/(m-1) - (n-1)/(m-1). Note that (mc+1-1)/(m-1) is an integer, so a is an integer iff n-1 is a multiple of m-1. Also a is positive iff mc+1 > n.
b = mc - a = (n-1)/(m-1) - (mc-1)/(m-1). So b is also an integer iff n-1 is a multiple of m-1, and is positive iff n > mc.
If n is a power of m, then we cannot find an integer c such that mc+1 > n > mc, so there are no solutions. Otherwise, there is a unique c such that mc+1 > n > mc.
Thus we can find positive integers a, b, c iff m > 1, n-1 is a multiple of m-1, n is not a power of m and the solution is then unique. 

Problem 2
Divide the unit square into 9 equal squares (forming a 3 x 3 array) and color the central square red. Now subdivide each of the 8 uncolored squares into 9 equal squares and color each central square red. Repeat n times, so that the side length of the smallest squares is 1/3n. How many squares are uncolored? What is the total red area as n → ∞?
Solution
8n uncolored squares after n steps. Total uncolored area = (8/9)n, so total red area = 1 - (8/9)n → 1 as n → ∞. 
Problem 3
ABC is a triangle and R any point on the segment AB. Let P be the intersection of the line BC and the line through A parallel to CR. Let Q be the intersection of the line AC and the line through B parallel to CR. Show that 1/AP + 1/BQ = 1/CR.
Solution
By similar triangles, CR/AP = BC/BP and CR/BQ = AC/AQ = CP/BP. Hence CR/AP + CR/BQ = 1.


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